Optimal. Leaf size=214 \[ \frac{\left (3 a^2-2 a b (2 p+5)+b^2 \left (4 p^2+16 p+15\right )\right ) \sinh (e+f x) \left (a+b \sinh ^2(e+f x)\right )^p \left (\frac{b \sinh ^2(e+f x)}{a}+1\right )^{-p} \, _2F_1\left (\frac{1}{2},-p;\frac{3}{2};-\frac{b \sinh ^2(e+f x)}{a}\right )}{b^2 f (2 p+3) (2 p+5)}-\frac{(3 a-b (2 p+7)) \sinh (e+f x) \left (a+b \sinh ^2(e+f x)\right )^{p+1}}{b^2 f (2 p+3) (2 p+5)}+\frac{\sinh (e+f x) \cosh ^2(e+f x) \left (a+b \sinh ^2(e+f x)\right )^{p+1}}{b f (2 p+5)} \]
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Rubi [A] time = 0.20449, antiderivative size = 214, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.217, Rules used = {3190, 416, 388, 246, 245} \[ \frac{\left (3 a^2-2 a b (2 p+5)+b^2 \left (4 p^2+16 p+15\right )\right ) \sinh (e+f x) \left (a+b \sinh ^2(e+f x)\right )^p \left (\frac{b \sinh ^2(e+f x)}{a}+1\right )^{-p} \, _2F_1\left (\frac{1}{2},-p;\frac{3}{2};-\frac{b \sinh ^2(e+f x)}{a}\right )}{b^2 f (2 p+3) (2 p+5)}-\frac{(3 a-b (2 p+7)) \sinh (e+f x) \left (a+b \sinh ^2(e+f x)\right )^{p+1}}{b^2 f (2 p+3) (2 p+5)}+\frac{\sinh (e+f x) \cosh ^2(e+f x) \left (a+b \sinh ^2(e+f x)\right )^{p+1}}{b f (2 p+5)} \]
Antiderivative was successfully verified.
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Rule 3190
Rule 416
Rule 388
Rule 246
Rule 245
Rubi steps
\begin{align*} \int \cosh ^5(e+f x) \left (a+b \sinh ^2(e+f x)\right )^p \, dx &=\frac{\operatorname{Subst}\left (\int \left (1+x^2\right )^2 \left (a+b x^2\right )^p \, dx,x,\sinh (e+f x)\right )}{f}\\ &=\frac{\cosh ^2(e+f x) \sinh (e+f x) \left (a+b \sinh ^2(e+f x)\right )^{1+p}}{b f (5+2 p)}+\frac{\operatorname{Subst}\left (\int \left (a+b x^2\right )^p \left (-a+b (5+2 p)-(3 a-b (7+2 p)) x^2\right ) \, dx,x,\sinh (e+f x)\right )}{b f (5+2 p)}\\ &=-\frac{(3 a-b (7+2 p)) \sinh (e+f x) \left (a+b \sinh ^2(e+f x)\right )^{1+p}}{b^2 f (3+2 p) (5+2 p)}+\frac{\cosh ^2(e+f x) \sinh (e+f x) \left (a+b \sinh ^2(e+f x)\right )^{1+p}}{b f (5+2 p)}+\frac{\left (3 a^2-2 a b (5+2 p)+b^2 \left (15+16 p+4 p^2\right )\right ) \operatorname{Subst}\left (\int \left (a+b x^2\right )^p \, dx,x,\sinh (e+f x)\right )}{b^2 f (3+2 p) (5+2 p)}\\ &=-\frac{(3 a-b (7+2 p)) \sinh (e+f x) \left (a+b \sinh ^2(e+f x)\right )^{1+p}}{b^2 f (3+2 p) (5+2 p)}+\frac{\cosh ^2(e+f x) \sinh (e+f x) \left (a+b \sinh ^2(e+f x)\right )^{1+p}}{b f (5+2 p)}+\frac{\left (\left (3 a^2-2 a b (5+2 p)+b^2 \left (15+16 p+4 p^2\right )\right ) \left (a+b \sinh ^2(e+f x)\right )^p \left (1+\frac{b \sinh ^2(e+f x)}{a}\right )^{-p}\right ) \operatorname{Subst}\left (\int \left (1+\frac{b x^2}{a}\right )^p \, dx,x,\sinh (e+f x)\right )}{b^2 f (3+2 p) (5+2 p)}\\ &=-\frac{(3 a-b (7+2 p)) \sinh (e+f x) \left (a+b \sinh ^2(e+f x)\right )^{1+p}}{b^2 f (3+2 p) (5+2 p)}+\frac{\cosh ^2(e+f x) \sinh (e+f x) \left (a+b \sinh ^2(e+f x)\right )^{1+p}}{b f (5+2 p)}+\frac{\left (3 a^2-2 a b (5+2 p)+b^2 \left (15+16 p+4 p^2\right )\right ) \, _2F_1\left (\frac{1}{2},-p;\frac{3}{2};-\frac{b \sinh ^2(e+f x)}{a}\right ) \sinh (e+f x) \left (a+b \sinh ^2(e+f x)\right )^p \left (1+\frac{b \sinh ^2(e+f x)}{a}\right )^{-p}}{b^2 f (3+2 p) (5+2 p)}\\ \end{align*}
Mathematica [F] time = 10.606, size = 0, normalized size = 0. \[ \int \cosh ^5(e+f x) \left (a+b \sinh ^2(e+f x)\right )^p \, dx \]
Verification is Not applicable to the result.
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Maple [F] time = 0.645, size = 0, normalized size = 0. \begin{align*} \int \left ( \cosh \left ( fx+e \right ) \right ) ^{5} \left ( a+b \left ( \sinh \left ( fx+e \right ) \right ) ^{2} \right ) ^{p}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (b \sinh \left (f x + e\right )^{2} + a\right )}^{p} \cosh \left (f x + e\right )^{5}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left ({\left (b \sinh \left (f x + e\right )^{2} + a\right )}^{p} \cosh \left (f x + e\right )^{5}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (b \sinh \left (f x + e\right )^{2} + a\right )}^{p} \cosh \left (f x + e\right )^{5}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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